See main article: 1800 United States presidential election.
| Election Name: | 1800 United States presidential election in Virginia |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1796 United States presidential election in Virginia |
| Previous Year: | 1796 |
| Next Election: | 1804 United States presidential election in Virginia |
| Next Year: | 1804 |
| Election Date: | October 31 – December 3, 1800 |
| Image1: | File:Thomas Jefferson by Rembrandt Peale, 1800.jpg |
| Nominee1: | Thomas Jefferson |
| Party1: | Democratic-Republican Party |
| Home State1: | Virginia |
| Electoral Vote1: | 21 |
| Country: | Virginia |
| Percentage1: | 77.28% |
| President | |
| Before Election: | John Adams |
| Before Party: | Federalist Party (United States) |
| After Election: | Thomas Jefferson |
| After Party: | Democratic-Republican Party |
| Popular Vote1: | 21,002 |
| Home State2: | Massachusetts |
| Popular Vote2: | 6,175 |
| Percentage2: | 22.72% |
| Nominee2: | John Adams |
| Party2: | Federalist |
The 1800 United States presidential election in Virginia was held between October 31 – December 3, 1800. Virginia voters chose 21 representatives, or electors to the Electoral College, who voted for President and Vice President.
Democratic-Republican Vice President Thomas Jefferson carried the state by taking all 21 electoral votes and over 77.2% of the popular votes.
| 1800 United States presidential election in Virginia[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | Thomas Jefferson | 21,002 | 77.28% | 21 | |
| Federalist | John Adams | 6,175 | 22.72% | 0 | |
| Totals | 4,512 | 100.00% | 21 | ||