1828 United States presidential election in Connecticut explained

See main article: 1828 United States presidential election.

Election Name:1828 United States presidential election in Connecticut
Country:Connecticut
Type:presidential
Ongoing:no
Previous Election:1824 United States presidential election in Connecticut
Previous Year:1824
Next Election:1832 United States presidential election in Connecticut
Next Year:1832
Election Date:October 31 – December 2, 1828
Image1:John Quincy Adams 1858 crop.jpg
Nominee1:John Quincy Adams
Party1:National Republican Party (United States)
Home State1:Massachusetts
Running Mate1:Richard Rush
Electoral Vote1:8
Popular Vote1:13,829
Percentage1:71.36%
Nominee2:Andrew Jackson
Party2:Democratic Party (United States)
Home State2:Tennessee
Running Mate2:John C. Calhoun
Electoral Vote2:0
Popular Vote2:4,448
Percentage2:22.95%
Map Size:250px

The 1828 United States presidential election in Connecticut took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Connecticut voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Connecticut by a margin of 48.41%.

With 71.36% of the popular vote, Connecticut would prove to be Adams' fourth strongest state in the 1828 election after Rhode Island, Massachusetts and Vermont.[1]

Results

1828 United States presidential election in Connecticut[2]
PartyCandidateVotesPercentageElectoral votes
National RepublicanJohn Quincy Adams (incumbent)13,82971.36%8
DemocraticAndrew Jackson4,44822.95%0
N/AOther1,1015.68%0
Totals19,378100.0%8

See also

Notes and References

  1. Web site: 1828 Presidential Election Statistics. Dave Leip’s Atlas of U.S. Presidential Elections. 2018-03-05.
  2. Web site: 1828 Presidential General Election Results - Connecticut. U.S. Election Atlas. 28 February 2013.