Tsankov Island | |
Map: | Antarctica#Antarctic Peninsula |
Map Relief: | yes |
Location: | Antarctica |
Coordinates: | -65.0661°N -64.1439°W |
Archipelago: | Wilhelm Archipelago |
Area Ha: | 9.48 |
Length M: | 625 |
Width M: | 216 |
Population: | uninhabited |
Country: | None |
Treaty System: | Antarctic Treaty System |
Tsankov Island (Bulgarian: Цанков остров|Tsankov ostrov, in Bulgarian pronounced as /t͡sɐnˈkɔf ˈɔstrof/) is the mostly ice-covered island 625 m long in west-southwest to west-northeast direction and 216 m wide in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 9.48 ha.[1]
The feature is named after the dermatologist Nikolay Tsankov, participant in the 2010/11 and subsequent Bulgarian Antarctic campaigns.[1]
Tsankov Island is located at -65.0661°N -64.1439°W, which is 293 m northwest of Stego Island, 175 m east of Bodloperka Island, 1.18 km southeast of Sprey Island and 1.25 km west-southwest of Taralezh Island. British mapping in 2001.